From e7017f320a9055d94ad06302443486eded5b8f77 Mon Sep 17 00:00:00 2001
From: "kurchan.jorge" <kurchan.jorge@gmail.com>
Date: Wed, 9 Dec 2020 14:47:02 +0000
Subject: Update on Overleaf.

---
 bezout.tex | 11 -----------
 1 file changed, 11 deletions(-)

(limited to 'bezout.tex')

diff --git a/bezout.tex b/bezout.tex
index 2917eda..d9aa415 100644
--- a/bezout.tex
+++ b/bezout.tex
@@ -333,17 +333,6 @@ limit as $\epsilon$ is varied.
 
 {\color{teal} {\bf somewhere else}
 
-Another instrument we have to study this problem is to compute the following partition function:
-\begin{equation}
-  \begin{aligned}
-    Z(a,\beta)&=\int dx\, dy \, e^{-\mathop{\mathrm{Re}}(\beta H_0)}\\
-     &\qquad\delta(\sum_i z_i^2-N) \delta\left(\sum_i y_i^2 -N \frac{a-1}{2}\right).
-  \end{aligned}
-\end{equation}
-The energy $\Re H_0, \Im H_0$ are in a one-to one relation with the temperatures $\beta_R,\beta_I$. The entropy $S(a,H_0) = \ln Z+ +\beta_{R} \langle \Re H_0 \rangle +\beta_I \langle \Im H_0\rangle$
-is the logarithm of the number of configurations of a given $(a,H_0)$.
-This problem may be solved exactly with replicas, {\em but it may also be simulated} \cite{Bray_1980_Metastable}.
-Consider for example the ground-state energy for given $a$, that is, the energy in the limit $\beta_R \rightarrow \infty$ taken adjusting  $\beta_I$ so that $\Im H_0=0$ . For $a=1$ this coincides with the ground-state of the real problem.
 
 {\bf somewhere} In Figure \ref{fig:desert} we show that for $\kappa<1$ there is always a gap of  $a$ close to one for which there are no solutions: this is natural, given that the $y$ contribution to the volume shrinks to zero as that of an $N$-dimensional sphere $\sim(a-1)^N$.
 For the case $K=1$ -- i.e. the analytic continuation of the usual real computation -- the situation
-- 
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