\documentclass[aps,prl,reprint,longbibliography,floatfix,fleqn]{revtex4-2} \usepackage[utf8]{inputenc} % why not type "Bézout" with unicode? \usepackage[T1]{fontenc} % vector fonts plz \usepackage[ colorlinks=true, urlcolor=purple, citecolor=purple, filecolor=purple, linkcolor=purple ]{hyperref} % ref and cite links with pretty colors \usepackage{amsmath, amssymb, graphicx, xcolor} % standard packages \begin{document} \title{Complex complex landscapes: saturating the Bézout bound} % change me \author{Jaron Kent-Dobias} \author{Jorge Kurchan} \affiliation{Laboratoire de Physique de l'Ecole Normale Supérieure, Paris, France} \date\today \begin{abstract} We study the saddle-points of the $p$-spin mode -- the best understood example of `complex (rugged) landscape' -- in the space in which all its $N$ variables are allowed to be complex. The problem becomes a system of $N$ random equations of degree $p-1$. We solve for quantities averaged over randomness in the $N \rightarrow \infty$ limit. We show that the number of solutions saturates the Bézout bound $\ln {\cal{N}}\sim N \ln (p-1) $\cite{Bezout_1779_Theorie}. The Hessian of each saddle is given by a random matrix of the form $M=a A^2+b B^2 +ic [A,B]_-+ d [A,B]_+$, where $A$ and $B$ are GOE matrices and $a-d$ real. Its spectrum has a transition from one-cut to two-cut that generalizes the notion of `threshold level' that is well-known in the real problem. In the case that the disorder is itself real, only the square-root of the total number solutions are real. In terms of real and imaginary parts of the energy, the solutions are divided in sectors where the saddles have different topological properties. \end{abstract} \maketitle Spin-glasses have long been considered the paradigm of `complex landscapes' of many variables, a subject that includes Neural Networks and optimization problems, most notably Constraint Satisfaction ones. The most tractable family of these are the mean-field spherical p-spin models defined by the energy: \begin{equation} \label{eq:bare.hamiltonian} H_0 = \sum_p \frac{c_p}{p!}\sum_{i_1\cdots i_p}^NJ_{i_1\cdots i_p}z_{i_1}\cdots z_{i_p}, \end{equation} where the $J_{i_1\cdots i_p}$ are real Gaussian variables and the $z_i$ are real and constrained to a sphere $\sum_i z_i^2=N$. If there is a single term of a given $p$, this is known as the `pure $p$-spin' model, the case we shall study here. This problem has been attacked from several angles: the replica trick to compute the Boltzmann--Gibbs distribution, a Kac--Rice \cite{Kac_1943_On, Rice_1939_The, Fyodorov_2004_Complexity} procedure (similar to the Fadeev--Popov integral) to compute the number of saddle-points of the energy function, and the gradient-descent -- or more generally Langevin -- dynamics staring from a high-energy configuration. Thanks to the relative simplicity of the energy, all these approaches are possible analytically in the large $N$ limit. In this paper we shall extend the study to the case where $z\in\mathbb C^N$ are and $J$ is a symmetric tensor whose elements are complex normal with $\overline{|J|^2}=p!/2N^{p-1}$ and $\overline{J^2}=\kappa\overline{|J|^2}$ for complex parameter $|\kappa|<1$. The constraint becomes $z^2=N$. The motivations for this paper are of two types. On the practical side, there are situations in which complex variables have in a disorder problem appear naturally: such is the case in which they are {\em phases}, as in random laser problems \cite{Antenucci_2015_Complex, etc}. Another problem where a Hamiltonian very close to ours has been proposed is the Quiver Hamiltonians \cite{Anninos_2016_Disordered} modeling Black Hole horizons in the zero-temperature limit. There is however a more fundamental reason for this study: we know from experience that extending a problem to the complex plane often uncovers an underlying simplicity that is hidden in the purely real case. Consider, for example, the procedure of starting from a simple, known Hamiltonian $H_{00}$ and studying $\lambda H_{00} + (1-\lambda H_{0} )$, evolving adiabatically from $\lambda=0$ to $\lambda=1$, as is familiar from quantum annealing. The $H_{00}$ is a polynomial of degree $p$ chosen to have simple, known roots. Because we are working in complex variables, and the roots are simple all the way (we shall confirm this), we may follow a root from $\lambda=0$ to $\lambda=1$. With real variables minima of functions appear and disappear, and this procedure is not possible. The same idea may be implemented by performing diffusion in the $J$'s, and following the roots, in complete analogy with Dyson's stochastic dynamics. Let us go back to our model. For the constraint we choose here $z^2=N$, rather than $|z|^2=N$, in order to preserve the holomorphic nature of the functions. In addition, the nonholomorphic spherical constraint has a disturbing lack of critical points nearly everywhere, since $0=\partial^* H=-p\epsilon z$ is only satisfied for $\epsilon=0$, as $z=0$ is forbidden by the constraint. It is enforced using the method of Lagrange multipliers: introducing the $\epsilon\in\mathbb C$, this gives \begin{equation} \label{eq:constrained.hamiltonian} H = H_0+\frac p2\epsilon\left(N-\sum_i^Nz_i^2\right). \end{equation} It is easy to see that {\em for a pure $p$-spin}, at any critical point $\epsilon=H/N$, the average energy. Since $H$ is holomorphic, a point is a critical point of its real part if and only if it is also a critical point of its imaginary part. The number of critical points of $H$ is therefore the number of critical points of $\mathop{\mathrm{Re}}H$. Writing $z=x+iy$, $\mathop{\mathrm{Re}}H$ can be interpreted as a real function of $2N$ real variables. The number of critical points it has is given by the usual Kac--Rice formula: \begin{equation} \label{eq:real.kac-rice} \begin{aligned} \mathcal N_J(\kappa,\epsilon) &= \int dx\,dy\,\delta(\partial_x\mathop{\mathrm{Re}}H)\delta(\partial_y\mathop{\mathrm{Re}}H) \\ &\qquad\times\left|\det\begin{bmatrix} \partial_x\partial_x\mathop{\mathrm{Re}}H & \partial_x\partial_y\mathop{\mathrm{Re}}H \\ \partial_y\partial_x\mathop{\mathrm{Re}}H & \partial_y\partial_y\mathop{\mathrm{Re}}H \end{bmatrix}\right|. \end{aligned} \end{equation} The Cauchy--Riemann equations may be used to write \eqref{eq:real.kac-rice} in a manifestly complex way. Using the Wirtinger derivative $\partial=\partial_x-i\partial_y$, one can write $\partial_x\mathop{\mathrm{Re}}H=\mathop{\mathrm{Re}}\partial H$ and $\partial_y\mathop{\mathrm{Re}}H=-\mathop{\mathrm{Im}}\partial H$. Carrying these transformations through, we have \begin{equation} \label{eq:complex.kac-rice} \begin{aligned} \mathcal N_J&(\kappa,\epsilon) = \int dx\,dy\,\delta(\mathop{\mathrm{Re}}\partial H)\delta(\mathop{\mathrm{Im}}\partial H) \\ &\qquad\qquad\qquad\times\left|\det\begin{bmatrix} \mathop{\mathrm{Re}}\partial\partial H & -\mathop{\mathrm{Im}}\partial\partial H \\ -\mathop{\mathrm{Im}}\partial\partial H & -\mathop{\mathrm{Re}}\partial\partial H \end{bmatrix}\right| \\ &= \int dx\,dy\,\delta(\mathop{\mathrm{Re}}\partial H)\delta(\mathop{\mathrm{Im}}\partial H) \left|\det[(\partial\partial H)^\dagger\partial\partial H]\right| \\ &= \int dx\,dy\,\delta(\mathop{\mathrm{Re}}\partial H)\delta(\mathop{\mathrm{Im}}\partial H) |\det\partial\partial H|^2. \end{aligned} \end{equation} This gives three equivalent expressions for the determinant of the Hessian: as that of a $2N\times 2N$ real matrix, that of an $N\times N$ Hermitian matrix, or the norm squared of that of an $N\times N$ complex symmetric matrix. These equivalences belie a deeper connection between the spectra of the corresponding matrices: each eigenvalue of the real matrix has a negative partner. For each pair $\pm\lambda$ of the real matrix, $\lambda^2$ is an eigenvalue of the Hermitian matrix and $|\lambda|$ is a \emph{singular value} of the complex symmetric matrix. The distribution of positive eigenvalues of the Hessian is therefore the same as the distribution of singular values of $\partial\partial H$, while both are the same as the distribution of square-rooted eigenvalues of $(\partial\partial H)^\dagger\partial\partial H$. The expression \eqref{eq:complex.kac-rice} is to be averaged over the $J$'s as $N \Sigma= \overline{\ln \mathcal N_J} = \int dJ \; \ln N_J$, a calculation that involves the replica trick. In most the parameter-space that we shall study here, the {\em annealed approximation} $N \Sigma \sim \ln \overline{ \mathcal N_J} = \ln \int dJ \; N_J$ is exact. A useful property of the Gaussian distributions is that gradient and Hessian may be seen to be independent \cite{Bray_2007_Statistics, Fyodorov_2004_Complexity}, so that we may treat the $\delta$-functions and the Hessians as independent. We compute each by taking the saddle point. The $\delta$-functions are converted to exponentials by the introduction of auxiliary fields $\hat z=\hat x+i\hat y$. The average over $J$ can then be performed. A generalized Hubbard--Stratonovich then allows a change of variables from the $4N$ original and auxiliary fields to eight bilinears defined by \begin{equation} \begin{aligned} Na=z^*\cdot z && N\hat c=\hat z\cdot\hat z && Nb=\hat z^*\cdot z \\ N\hat a=\hat z^*\cdot\hat z && Nd=\hat z\cdot z \end{aligned} \end{equation} and their conjugates. The result is, to leading order in $N$, \begin{equation} \label{eq:saddle} \overline{\mathcal N_J}(\kappa,\epsilon) = \int da\,d\hat a\,db\,db^*d\hat c\,d\hat c^*dd\,dd^*e^{Nf(a,\hat a,b,\hat c,d)}, \end{equation} where \begin{widetext} \textcolor{red}{\textbf{[appendix?? I'm putting too much right now so as to trim later...]}} \begin{equation} f=2+\frac12\log\det\frac12\begin{bmatrix} 1 & a & d & b \\ a & 1 & b^* & d^* \\ d & b^* & \hat c & \hat a \\ b & d^* & \hat a & \hat c^* \end{bmatrix} +\mathop{\mathrm{Re}}\left\{\frac18\left[\hat aa^{p-1}+(p-1)|d|^2a^{p-2}+\kappa(\hat c^*+(p-1)b^2)\right]-\epsilon b\right\} +\int d\lambda\,\rho(\lambda)\log|\lambda|^2 \end{equation} where $\rho(\lambda)$, the distribution of eigenvalues $\lambda$ of $\partial\partial H$, is dependant on $a$ alone. This function has a maximum in $\hat a$, $b$, $\hat c$, and $d$ at which its value is (for simplicity, with $\kappa\in\mathbb R$) \begin{equation} \begin{aligned} f(a)&=1+\frac12\log\left(\frac4{p^2}\frac{a^2-1}{a^{2(p-1)}-\kappa^2}\right)+\int d\lambda\,\rho(\lambda)\log|\lambda|^2 \\ &\hspace{80pt}-\frac{a^p(1+p(a^2-1))-a^2\kappa}{a^{2p}+a^p(a^2-1)(p-1)-a^2\kappa^2}(\mathop{\mathrm{Re}}\epsilon)^2 -\frac{a^p(1+p(a^2-1))+a^2\kappa}{a^{2p}-a^p(a^2-1)(p-1)-a^2\kappa^2}(\mathop{\mathrm{Im}}\epsilon)^2, \end{aligned} \end{equation} \end{widetext} This leaves a single parameter, $a$, which dictates the magnitude of $z^*\cdot z$, or alternatively the magnitude $y^2$ of the imaginary part. The latter vanishes as $a\to1$, where we should recover known results for the real $p$-spin. The Hessian of \eqref{eq:constrained.hamiltonian} is $\partial\partial H=\partial\partial H_0-p\epsilon I$, or the Hessian of \eqref{eq:bare.hamiltonian} with a constant added to its diagonal. The eigenvalue distribution $\rho$ of the constrained Hessian is therefore related to the eigenvalue distribution $\rho_0$ of the unconstrained one by a similar shift, or $\rho(\lambda)=\rho_0(\lambda+p\epsilon)$. The Hessian of \eqref{eq:bare.hamiltonian} is \begin{equation} \label{eq:bare.hessian} \partial_i\partial_jH_0 =\frac{p(p-1)}{p!}\sum_{k_1\cdots k_{p-2}}^NJ_{ijk_1\cdots k_{p-2}}z_{k_1}\cdots z_{k_{p-2}}, \end{equation} {\color{red} \bf here I would explain the question of the det and also of the appearance of the gap, would draw a picture of ellipse etc, and would send the reader to an appendix for most of this part of the calculation} which makes its ensemble that of Gaussian complex symmetric matrices. Given its variances $\overline{|\partial_i\partial_j H_0|^2}=p(p-1)a^{p-2}/2N$ and $\overline{(\partial_i\partial_j H_0)^2}=p(p-1)\kappa/2N$, $\rho_0(\lambda)$ is constant inside the ellipse \begin{equation} \label{eq:ellipse} \left(\frac{\mathop{\mathrm{Re}}(\lambda e^{i\theta})}{a^{p-2}+|\kappa|}\right)^2+ \left(\frac{\mathop{\mathrm{Im}}(\lambda e^{i\theta})}{a^{p-2}-|\kappa|}\right)^2 <\frac{p(p-1)}{2a^{p-2}} \end{equation} where $\theta=\frac12\arg\kappa$ \cite{Nguyen_2014_The}. The eigenvalue spectrum of $\partial\partial H$ therefore is that of an ellipse whose center is shifted by $p\epsilon$. \begin{figure}[htpb] \centering \includegraphics{fig/spectra_0.0.pdf} \includegraphics{fig/spectra_0.5.pdf}\\ \includegraphics{fig/spectra_1.0.pdf} \includegraphics{fig/spectra_1.5.pdf} \caption{ Eigenvalue and singular value spectra of the matrix $\partial\partial H$ for $p=3$, $a=\frac54$, and $\kappa=\frac34e^{i3\pi/4}$ with (a) $\epsilon=0$, (b) $\epsilon=\frac12|\epsilon_{\mathrm{th}}|$, (c) $\epsilon=|\epsilon_{\mathrm{th}}|$, and (d) $\epsilon=\frac32|\epsilon_{\mathrm{th}}|$. The shaded region of each inset shows the support of the eigenvalue distribution. The solid line on each plot shows the distribution of singular values, while the overlaid histogram shows the empirical distribution from $2^{10}\times2^{10}$ complex normal matrices with the same covariance and diagonal shift as $\partial\partial H$. } \label{fig:spectra} \end{figure} The eigenvalue spectrum of the Hessian of the real part, or equivalently the eigenvalue spectrum of $(\partial\partial H)^\dagger\partial\partial H$, is the singular value spectrum of $\partial\partial H$. When $\kappa=0$ and the elements of $J$ are standard complex normal, this corresponds to a complex Wishart distribution. For $\kappa\neq0$ the problem changes, and to our knowledge a closed form is not known. We have worked out an implicit form for this spectrum using the saddle point of a replica symmetric calculation for the Green function. The result is \begin{widetext} \begin{equation} G(\sigma)=\lim_{n\to0}\int d\alpha\,d\chi\,d\chi^*\frac\alpha2 \exp nN\left\{ 1+\frac{p(p-1)}{16}a^{p-2}\alpha^2-\frac{\alpha\sigma}2+\frac12\log(\alpha^2-|\chi|^2) +\frac p4\mathop{\mathrm{Re}}\left(\frac{(p-1)}8\kappa^*\chi^2-\epsilon^*\chi\right) \right\} \end{equation} \end{widetext} The argument of the exponential has several saddles, but the one with the smallest value of $\mathop{\mathrm{Re}}\alpha$ gives the correct solution \textcolor{red}{\textbf{why????? we never figured this out...}}. The transition from a one-cut to two-cut singular value spectrum naturally corresponds to the origin leaving the support of the eigenvalue spectrum. Weyl's theorem requires that the product over the norm of all eigenvalues must not be greater than the product over all singular values \cite{Weyl_1912_Das}. Therefore, the absence of zero eigenvalues implies the absence of zero singular values. The determination of the threshold energy is therefore reduced to a geometry problem, and yields \begin{equation} \label{eq:threshold.energy} |\epsilon_{\mathrm{th}}|^2 =\frac{p-1}{2p}\frac{(1-|\delta|^2)^2a^{p-2}} {1+|\delta|^2-2|\delta|\cos(\arg\kappa+2\arg\epsilon)} \end{equation} for $\delta=\kappa a^{-(p-2)}$. % This is kind of a boring definition... \begin{equation} \label{eq:count.def.marginal} \overline{\mathcal N}(\kappa,\epsilon) =\int da\,\overline{\mathcal N}(\kappa,\epsilon,a) \end{equation} \begin{equation} \label{eq:count.zero.energy} \overline{\mathcal N}(\kappa,0,a) =\left[(p-1)a^{p-1}\sqrt{\frac{1-a^{-2}}{a^{2(p-1)}-|\kappa|^2}}\right]^N \end{equation} \begin{equation} \overline{\mathcal N}(\kappa,\epsilon) =\lim_{a\to\infty}\overline{\mathcal N}(\kappa,\epsilon,a) =(p-1)^N \end{equation} For $|\kappa|<1$, \begin{equation} \lim_{a\to1}\overline{\mathcal N}(\kappa,\epsilon,a) =0 \end{equation} \begin{equation} \lim_{a\to1}\overline{\mathcal N}(1,0,a) =(p-1)^{N/2} \end{equation} {\color{teal} {\bf somewhere else} Another instrument we have to study this problem is to compute the following partition function: \begin{equation} \begin{aligned} Z(a,\beta)&=\int dx\, dy \, e^{-\mathop{\mathrm{Re}}(\beta H_0)}\\ &\qquad\delta(\sum_i z_i^2-N) \delta\left(\sum_i y_i^2 -N \frac{a-1}{2}\right). \end{aligned} \end{equation} The energy $\Re H_0, \Im H_0$ are in a one-to one relation with the temperatures $\beta_R,\beta_I$. The entropy $S(a,H_0) = \ln Z+ +\beta_{R} \langle \Re H_0 \rangle +\beta_I \langle \Im H_0\rangle$ is the logarithm of the number of configurations of a given $(a,H_0)$. This problem may be solved exactly with replicas, {\em but it may also be simulated} \cite{Bray_1980_Metastable}. Consider for example the ground-state energy for given $a$, that is, the energy in the limit $\beta_R \rightarrow \infty$ taken adjusting $\beta_I$ so that $\Im H_0=0$ . For $a=1$ this coincides with the ground-state of the real problem. \begin{figure}[htpb] \centering \includegraphics{fig/desert.pdf} \caption{ The minimum value of $a$ for which the complexity is positive as a function of (real) energy $\epsilon$ for the pure 4-spin model at several values of $\kappa$. } \end{figure} } \bibliographystyle{apsrev4-2} \bibliography{bezout} \end{document}