From 6df867fda7aa0b0a42ef1933615ef0b40ff50209 Mon Sep 17 00:00:00 2001 From: "kurchan.jorge" Date: Wed, 6 Jul 2022 14:01:10 +0000 Subject: Update on Overleaf. --- frsb_kac-rice.tex | 2 +- 1 file changed, 1 insertion(+), 1 deletion(-) (limited to 'frsb_kac-rice.tex') diff --git a/frsb_kac-rice.tex b/frsb_kac-rice.tex index 9fc4b34..04cac67 100644 --- a/frsb_kac-rice.tex +++ b/frsb_kac-rice.tex @@ -842,7 +842,7 @@ The complexities are The maximum is given by $\Sigma_1'=\Sigma_2'=\hat \beta$, provided it occurs in the phase in which both $\Sigma_1$ and $\Sigma_2$ are non-zero. The two systems are `thermalized', and it is easy to see that, because many points contribute, the overlap between two -global configurations $$\frac1 {2N}({\mathbf s^1},{\mathbf \sigma^1})\cdot ({\mathbf s^2},{\mathbf \sigma^2})=0$$ This is the `annealed' phase of a Kac-Rice calculation. +global configurations $$\frac1 {2N}({\mathbf s^1},{\mathbf \sigma^1})\cdot ({\mathbf s^2},{\mathbf \sigma^2})=\frac1 {2N}[ {\mathbf s^1}\cdot {\mathbf s^2}+ {\mathbf \sigma^1}\cdot {\mathbf \sigma^2}] =0$$ This is the `annealed' phase of a Kac-Rice calculation. Now start going down in energy, or up in $\hat \beta$: there will be a point $e_c$, $\hat \beta_c$ at which one of the subsystems freezes at its lower energy density, say it is system one, -- cgit v1.2.3-70-g09d2