From 4f03a48fc19933764b67a59a0e48547d8720e9ec Mon Sep 17 00:00:00 2001
From: Jaron Kent-Dobias <jaron@kent-dobias.com>
Date: Wed, 13 Jul 2022 13:18:32 +0200
Subject: Tiny disclaimer.

---
 frsb_kac-rice.tex | 11 ++++++-----
 1 file changed, 6 insertions(+), 5 deletions(-)

(limited to 'frsb_kac-rice.tex')

diff --git a/frsb_kac-rice.tex b/frsb_kac-rice.tex
index ec3a933..10552b6 100644
--- a/frsb_kac-rice.tex
+++ b/frsb_kac-rice.tex
@@ -536,11 +536,12 @@ matrix products and Hadamard products. In particular, the determinant of the blo
 \begin{equation}
   \ln\det\begin{bmatrix}C&iR\\iR&D\end{bmatrix}=\ln\det(CD+R^2)
 \end{equation}
-This is straightforward to write down at $k$RSB, since the product and sum of
-the hierarchical matrices is still a hierarchical matrix. The algebra of
-hierarchical matrices is reviewed in \S\ref{sec:dict}. Using the product formula
-\eqref{eq:replica.prod}, one can write down the hierarchical matrix $CD+R^2$,
-and then compute the $\ln\det$ using the formula \eqref{eq:replica.logdet}.
+This is straightforward (if strenous) to write down at $k$RSB, since the
+product and sum of the hierarchical matrices is still a hierarchical matrix.
+The algebra of hierarchical matrices is reviewed in \S\ref{sec:dict}. Using the
+product formula \eqref{eq:replica.prod}, one can write down the hierarchical
+matrix $CD+R^2$, and then compute the $\ln\det$ using the formula
+\eqref{eq:replica.logdet}.
 
 The extremal conditions are given by differentiating the complexity with
 respect to its parameters, yielding
-- 
cgit v1.2.3-70-g09d2

