From 568324cd4bc0cf2dd6a81464b1c4c700ee7ebfa5 Mon Sep 17 00:00:00 2001
From: Jaron Kent-Dobias <jaron@kent-dobias.com>
Date: Tue, 29 Oct 2024 10:22:37 +0100
Subject: Another tweak to superbases.

---
 marginal.tex | 10 +++++-----
 1 file changed, 5 insertions(+), 5 deletions(-)

(limited to 'marginal.tex')

diff --git a/marginal.tex b/marginal.tex
index c8d0b8b..88809d2 100644
--- a/marginal.tex
+++ b/marginal.tex
@@ -1802,13 +1802,13 @@ Integrals involving superfields contracted into such operators result in schemat
 \end{equation}
 where the usual role of the determinant is replaced by the superdeterminant.
 The superdeterminant can be defined using the ordinary determinant by writing a
-block version of the matrix $M$. If $\mathbf e(1)=\{1,i\bar\theta_1\theta_1\}$ is
+block version of the matrix $M$. If $\mathbf e(1)=\{1,\bar\theta_1\theta_1\}$ is
 the basis vector of the even subspace of the superspace and $\mathbf
-f(1)=\{i\bar\theta_1,i\theta_1\}$ is that of the odd subspace, dual bases $\mathbf e^\dagger(1)=\{i\bar\theta_1\theta_1,1\}$ and $\mathbf f^\dagger(1)=\{-\theta_1,\bar\theta_1\}$ can be defined by the requirement that
+f(1)=\{\bar\theta_1,\theta_1\}$ is that of the odd subspace, dual bases $\mathbf e^\dagger(1)=\{\bar\theta_1\theta_1,1\}$ and $\mathbf f^\dagger(1)=\{-\theta_1,\bar\theta_1\}$ can be defined by the requirement that
 \begin{align}
-  &\int d1\,e_i^\dagger(1)e_j(1)=i\delta_{ij}
+  &\int d1\,e_i^\dagger(1)e_j(1)=\delta_{ij}
   &&
-  \int d1\,f_i^\dagger(1)f_j(1)=i\delta_{ij} \\
+  \int d1\,f_i^\dagger(1)f_j(1)=\delta_{ij} \\
   &\int d1\,e_i^\dagger(1)f_j(1)=0
   &&
   \int d1\,f_i^\dagger(1)e_j(1)=0
@@ -1825,7 +1825,7 @@ block representation of $M$ in analogy to the matrix form of an operator in quan
     &
     \mathbf f^\dagger(1)M(1,2)\mathbf f(2)
   \end{bmatrix}
-  =i\begin{bmatrix}
+  =\begin{bmatrix}
     A & B \\ C & D
   \end{bmatrix}
 \end{equation}
-- 
cgit v1.2.3-70-g09d2

