From feb65b98ee9e264f30f8a0e13206f18ac98b6c02 Mon Sep 17 00:00:00 2001
From: Jaron Kent-Dobias <jaron@kent-dobias.com>
Date: Mon, 10 Jun 2024 19:34:08 +0200
Subject: Two small fixes.

---
 marginal.tex | 4 ++--
 1 file changed, 2 insertions(+), 2 deletions(-)

(limited to 'marginal.tex')

diff --git a/marginal.tex b/marginal.tex
index 024b0ac..95955b5 100644
--- a/marginal.tex
+++ b/marginal.tex
@@ -982,7 +982,7 @@ $f$ is an arbitrary function, then
 \end{equation}
 This kind of behavior of integrals over the Grassmann indices makes them useful
 for compactly expressing the Kac--Rice measure. To see why, consider the
-specific superspace $\mathbb R^{N|2}$, where an arbitrary vector can be expression as
+specific superspace $\mathbb R^{N|2}$, where an arbitrary vector can be expressed as
 \begin{equation}
   \pmb\phi(1)=\mathbf x+\bar\theta_1\pmb\eta+\bar{\pmb\eta}\theta_1+\bar\theta_1\theta_1i\hat{\mathbf x}
 \end{equation}
@@ -1038,7 +1038,7 @@ Integrals involving superfields contracted into such operators result in schemat
 \end{equation}
 where the usual role of the determinant is replaced by the superdeterminant.
 The superdeterminant can be defined using the ordinary determinant by writing a
-block version of the matrix $M$: if $\mathbf e(1)=\{1,\bar\theta_1\theta\}$ is
+block version of the matrix $M$: if $\mathbf e(1)=\{1,\bar\theta_1\theta_1\}$ is
 the basis vector of the even subspace of the superspace and $\mathbf
 f(1)=\{\bar\theta_1,\theta_1\}$ is that of the odd subspace, then we can form a
 block representation of $M$ in analogy to the matrix form of an operator in quantum mechanics by
-- 
cgit v1.2.3-70-g09d2

