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author | Jaron Kent-Dobias <jaron@kent-dobias.com> | 2019-08-24 15:58:09 -0400 |
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committer | Jaron Kent-Dobias <jaron@kent-dobias.com> | 2019-08-24 15:58:09 -0400 |
commit | bf115d332761635d19084ffbef296ee1a518ecd3 (patch) | |
tree | 4623b5d7c16fa3bb5b309260ed4086fc668deb5b | |
parent | 57151805ef46c88b532f94826930ea366862be14 (diff) | |
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small clarification
-rw-r--r-- | main.tex | 3 |
1 files changed, 2 insertions, 1 deletions
@@ -371,9 +371,10 @@ $\langle\epsilon\rangle$ (or $\eta_\star(\langle\epsilon\rangle)=\langle\eta\rangle$) yields \begin{equation} \bigg(\frac{\delta\eta_\star[\epsilon](x)}{\delta\epsilon_\X(x')}\bigg)^\recip\bigg|_{\epsilon=\langle\epsilon\rangle} - =-\frac2b\chi^\recip(x,x')-\frac{b}{2C_\X}\delta(x-x'). + =-\frac2b\chi^\recip(x,x')-\frac{b}{2C_\X}\delta(x-x'), \label{eq:recip.deriv.op} \end{equation} +where $\chi^\recip$ is the \op\ susceptibilty given by \eqref{eq:sus_def}. Upon substitution into \eqref{eq:big.boy} and taking the Fourier transform of the result, we finally arrive at \begin{equation} |