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authorJaron Kent-Dobias <jaron@kent-dobias.com>2024-06-10 19:34:08 +0200
committerJaron Kent-Dobias <jaron@kent-dobias.com>2024-06-10 19:34:08 +0200
commitfeb65b98ee9e264f30f8a0e13206f18ac98b6c02 (patch)
tree9262ccbebea7a9b1828429d8b4ed1d81c97bc245
parent2de476de17aea90b040875a7e3e87c308944a035 (diff)
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Two small fixes.
-rw-r--r--marginal.tex4
1 files changed, 2 insertions, 2 deletions
diff --git a/marginal.tex b/marginal.tex
index 024b0ac..95955b5 100644
--- a/marginal.tex
+++ b/marginal.tex
@@ -982,7 +982,7 @@ $f$ is an arbitrary function, then
\end{equation}
This kind of behavior of integrals over the Grassmann indices makes them useful
for compactly expressing the Kac--Rice measure. To see why, consider the
-specific superspace $\mathbb R^{N|2}$, where an arbitrary vector can be expression as
+specific superspace $\mathbb R^{N|2}$, where an arbitrary vector can be expressed as
\begin{equation}
\pmb\phi(1)=\mathbf x+\bar\theta_1\pmb\eta+\bar{\pmb\eta}\theta_1+\bar\theta_1\theta_1i\hat{\mathbf x}
\end{equation}
@@ -1038,7 +1038,7 @@ Integrals involving superfields contracted into such operators result in schemat
\end{equation}
where the usual role of the determinant is replaced by the superdeterminant.
The superdeterminant can be defined using the ordinary determinant by writing a
-block version of the matrix $M$: if $\mathbf e(1)=\{1,\bar\theta_1\theta\}$ is
+block version of the matrix $M$: if $\mathbf e(1)=\{1,\bar\theta_1\theta_1\}$ is
the basis vector of the even subspace of the superspace and $\mathbf
f(1)=\{\bar\theta_1,\theta_1\}$ is that of the odd subspace, then we can form a
block representation of $M$ in analogy to the matrix form of an operator in quantum mechanics by