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author | Jaron Kent-Dobias <jaron@kent-dobias.com> | 2022-02-03 17:37:07 +0100 |
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committer | Jaron Kent-Dobias <jaron@kent-dobias.com> | 2022-02-03 17:37:07 +0100 |
commit | 1e565370ddf77e0ce923920b97f8f5409aa2696d (patch) | |
tree | 15e7a76836999b3010ff601c5363ce03c73fa79b | |
parent | c71b46b9d779f783303da5401aff8f6246242b4d (diff) | |
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Fixed a reference.
-rw-r--r-- | stokes.tex | 2 |
1 files changed, 1 insertions, 1 deletions
@@ -239,7 +239,7 @@ answer is, we need the minimal set which produces a contour between the same places. Simply stated, if $\Omega=\mathbb R$ produced a phase space integral running along the real line from left to right, then our contour must likewise take one continuously from left to right, perhaps with detours to well-behaved -places at infinity (see Fig.~\ref{fig:1d.thimble}). The less simply stated versions follows. +places at infinity (see Fig.~\ref{fig:thimble.homology}). The less simply stated versions follows. Let $\tilde\Omega_T$ be the set of all points $z\in\tilde\Omega$ such that $\operatorname{Re}\beta\mathcal S(z)\geq T$, where we will take $T$ to be a very, |