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authorJaron Kent-Dobias <jaron@kent-dobias.com>2022-02-07 12:17:59 +0100
committerJaron Kent-Dobias <jaron@kent-dobias.com>2022-02-07 12:17:59 +0100
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Wrote paragraph discussing thimble rotation with the phase of β.
-rw-r--r--stokes.tex16
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diff --git a/stokes.tex b/stokes.tex
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--- a/stokes.tex
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@@ -438,6 +438,22 @@ eigenvalue problem. If we did not know the eigenvalues were real, we could
still see it from the second implied equation, $(\beta\partial\partial\mathcal
S)^*v^*=\lambda v$, which is the conjugate of the first if $\lambda^*=\lambda$.
+The effect of changing the phase of $\beta$ is revealed by
+\eqref{eq:generalized.eigenproblem}. Writing $\beta=|\beta|e^{i\phi}$ and
+dividing both sides by $|\beta|e^{i\phi/2}$, one finds
+\begin{equation}
+ \partial\partial\mathcal S(e^{i\phi/2}v)
+ =\frac{\lambda}{|\beta|}e^{-i\phi/2}v^*
+ =\frac{\lambda}{|\beta|}(e^{i\phi/2}v)^*
+\end{equation}
+Therefore, one only needs to consider solutions to the eigenproblem for the
+action alone, $\partial\partial\mathcal Sv_0=\lambda_0 v_0^*$, and then rotate the
+resulting vectors by a constant phase corresponding to half the phase of
+$\beta$ or $v(\phi)=v_0e^{-i\phi/2}$. One can see this in the examples of Figs. \ref{fig:1d.stokes} and
+\ref{fig:thimble.orientation}, where increasing the argument of $\beta$ from
+left to right produces a clockwise rotation in the thimbles in the
+complex-$\theta$ plane.
+
Something somewhat hidden in the structure of the real hessian but more clear
in its complex form is that each eigenvalue comes in a pair, since
\begin{equation}