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authorJaron Kent-Dobias <jaron@kent-dobias.com>2022-02-26 00:19:28 +0100
committerJaron Kent-Dobias <jaron@kent-dobias.com>2022-02-26 00:19:28 +0100
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Explicit formula for the complex complexity.
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diff --git a/stokes.tex b/stokes.tex
index 54b0b64..d4b0d38 100644
--- a/stokes.tex
+++ b/stokes.tex
@@ -1273,6 +1273,45 @@ related directly to the magnitude of the imaginary part of $z$, since
$z^\dagger z=x^Tx+y^Ty=N+2y^Ty$. We therefore define $Y=\frac1N(z^\dagger
z-N)$, the specific measure of the distance into the complex plane from the
real sphere. The complexity can then be written
+\begin{equation}
+ \Sigma
+ =
+ \log(p-1)-\frac12\log\left(
+ \frac{1-r^{-2(p-1)}}{1-r^{-2}}
+ \right)
+ -\frac{(\operatorname{Re}\epsilon)^2}{R_+^2}-\frac{(\operatorname{Im}\epsilon)^2}{R_-^2}
+ +I_p(\epsilon/\epsilon_\mathrm{th})
+\end{equation}
+\begin{equation}
+ R_\pm^2=\frac{p-1}2\frac{(r^{p-2}\pm1)\left[
+ r^{2(p-1)}\pm(p-1)r^{p-2}(r^2-1)-1
+ \right]}{
+ 1+r^{2(p-2)}\left[p(p-2)(r^2-1)-1\right]
+ }
+\end{equation}
+$I_p(u)=0$ if $|\epsilon|^2<|\epsilon_\mathrm{th}|^2$.
+\begin{eqnarray}
+ I_p(u)
+ &=
+ \left(\frac12+\frac1{r^{p-2}-1}\right)^{-1}(\operatorname{Re}u)^2
+ -
+ \left(\frac12-\frac1{r^{p-2}+1}\right)^{-1}(\operatorname{Im}u)^2\\
+ &\qquad-\log\left(
+ r^{p-2}\left|
+ u+\sqrt{u^2-1}
+ \right|^2
+ \right)+2\operatorname{Re}
+ \left(
+ u\sqrt{u^2-1}
+ \right)
+\end{eqnarray}
+where the branch of the square roots are chosen such that the real part of the
+root has the opposite sign as the real part of $u$, e.g., if
+$\operatorname{Re}u<0$ then $\operatorname{Re}\sqrt{u^2-1}>0$. If the real part
+is zero, then the sign is taken so that the imaginary part of the root has the
+opposite sign of the imaginary part of $u$.
+
+
\subsection{Pure \textit{p}-spin: where are my neighbors?}