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author | Jaron Kent-Dobias <jaron@kent-dobias.com> | 2025-03-10 15:07:53 -0300 |
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committer | Jaron Kent-Dobias <jaron@kent-dobias.com> | 2025-03-10 15:07:53 -0300 |
commit | ef9d4e4dd68cc6b8dd323f7bfa19a35fe7f6a17f (patch) | |
tree | 6910e3380abd9b3c5022a1cb61822ad0251e1ead | |
parent | 2a2a4e5d4b3b700ce27e7f948e6ab6f61e18693b (diff) | |
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Comment on report #2, third question
Discussed the relationship between the RSB instability in the Euler
characteristic calculatian and that of equilibrium in the spherical spin
glass and cost function cases.
-rw-r--r-- | referee_response.md | 6 |
1 files changed, 3 insertions, 3 deletions
diff --git a/referee_response.md b/referee_response.md index 7f939eb..08c463a 100644 --- a/referee_response.md +++ b/referee_response.md @@ -26,13 +26,13 @@ Requested changes 4- Include a comment stating that the functions in equation (7) are Morse, which justifies the use of equation (6). The Smale condition is mentioned, but not explained. Recommendation -Publish (meets expectations and criteria for this Journal) -(ii) It is mentioned that the naive satisfiability threshold predicted from the vanishing of (12) coincides with the threshold obtained within the replica symmetric analysis of the cost function (3). By reading the manuscript, I have missed if/how the satisfiability threshold arising from the analysis of the average Euler characteristics compares with the threshold obtained from the zero-temperature analysis of the equilibrium problem with energy (3): could the Author comment on this? +(iv) If understand correctly, the vector x0 is arbitrary and it is introduced with the purpose of decomposing the contributions to the Euler characteristics in terms of m. Given the arbitrarily of x0, one would naively expect that the “observable” part of the solution space corresponds to m=0, and that any analysis of the constraint satisfaction problem that is x0-independent should be unable to pick up the transition between Regime II and Regime III: is this the case? 1. In fact, the action is not complex when evaluated at m_* for V² > V_on² even though m_* itself becomes complex: the action remains real but becomes negative in this regime. This means that the contribution of these complex-m_* solutions in this regime shrinks with increasing N, and rather than representing a subleading but exponentially large (or even order 1) contribution to the Euler characteristic, their contribution is negligible. 2. The reference "A continuous constraint satisfaction problem for the rigidity transition in confluent tissues", which performs the FRSB treatment of the zero-temperature equilibrium problem for the case where f(q) = ½ q² and α = ¼, estimates V_SAT ≃ 1.871. Our calculation instead predicts V_SAT = 1.867229…. In private correspondence with the author of the quoted reference, they indicated that such a discrepancy could easily be due to inaccuracy in the numeric PDE treatment of the FRSB equilibrium problem and that they were not concerned by the seeming inconsistency. So, for the moment the two treatments are consistent but the agreement is not precise. A small discussion of this has been added in a footnote to the manuscript. - 3. + 3. The irrelevance of RSB to the spherical spin glasses represented in the α → 0 limit of the included phase diagrams is expected. In both the pure spherical models (Fig. 3) and the mixed 1+2 models (Fig. 4) the equilibrium measure is always either replica symmetric or 1RSB, and the distribution of stationary points in both is always replica symmetric. However, the paper does include a discussion of the consistency between the RSB instability predicted by our second moment calculation and the appearance of RSB in the complexity of the spherical spin glasses, at the end of Appendix D (they are consistent). Not said in the initial manuscript is that this agreement also exists with the instability in the zero-temperature equilibrium measure, whose calculation is an intermediate step in finding the quenched shattering energy. + If the referee is also curious about the agreement between RSB instabilities in the zero-temperature equilibrium treatment of the cost function when α > 0, we addressed this briefly in the final paragraph of Appendix C. There are regions of the SAT–UNSAT transition for the case f(q) = ½ q² where the equilibrium cost function is FRSB, where this calculation does not have an instability. As noted in that paragraph, there are reasons to believe that this is a trait of the cost function itself, since the cost function is predicted to have such an instability for a mundane energy level set of the pure 2-spin spherical spin glass where no RSB occurs. 4. Maybe?? # Report #3 |