diff options
| author | Jaron Kent-Dobias <jaron@kent-dobias.com> | 2024-10-29 14:00:55 +0100 |
|---|---|---|
| committer | Jaron Kent-Dobias <jaron@kent-dobias.com> | 2024-10-29 14:00:55 +0100 |
| commit | d944977b38915e8fe51ef1cca68b95d0a8107217 (patch) | |
| tree | 6570f29a30794032f8259207d41ea26642cf2dbb | |
| parent | 79309cd70841ecc1a0c34776ab962785c1e6ebce (diff) | |
| download | marginal-d944977b38915e8fe51ef1cca68b95d0a8107217.tar.gz marginal-d944977b38915e8fe51ef1cca68b95d0a8107217.tar.bz2 marginal-d944977b38915e8fe51ef1cca68b95d0a8107217.zip | |
Wording tweak.
| -rw-r--r-- | marginal.tex | 2 |
1 files changed, 1 insertions, 1 deletions
diff --git a/marginal.tex b/marginal.tex index 1f1143c..30d3dce 100644 --- a/marginal.tex +++ b/marginal.tex @@ -1394,7 +1394,7 @@ Unlike in the spherical and multispherical spin glasses, the value $\mu^*$ defined in \eqref{eq:mu.star} giving the typical value of $\frac1N\operatorname{Tr}\partial\partial H$ is not always zero. Instead $\mu^*=-f'(0)$, nonzero where there is a linear term in $V$. Fixing the trace -of the Hessian is therefore equivalent to setting $\omega=\mu+f'(0)$. +of the Hessian is therefore equivalent to constraining the value of the Lagrange multiplier $\omega=\mu+f'(0)$. The derivation of the marginal complexity for this model is complicated, but |